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[REF][partner_firstname] Method refactoring to use algorithms in other model

14.0
Adrien Peiffer (ACSONE) 9 years ago
committed by Luis Torres
parent
commit
5489d00358
  1. 23
      partner_firstname/models.py

23
partner_firstname/models.py

@ -38,12 +38,16 @@ class ResPartner(models.Model):
required=False,
store=True)
@api.model
def _get_computed_name(self, lastname, firstname):
"""Write the 'name' field according to splitted data."""
return u" ".join((p for p in (lastname, firstname) if p))
@api.one
@api.depends("firstname", "lastname")
def _compute_name(self):
"""Write the 'name' field according to splitted data."""
self.name = u" ".join((p for p in (self.lastname,
self.firstname) if p))
self.name = self._get_computed_name(self.lastname, self.firstname)
@api.one
def _inverse_name_after_cleaning_whitespace(self):
@ -65,8 +69,8 @@ class ResPartner(models.Model):
else:
self._inverse_name()
@api.one
def _inverse_name(self):
@api.model
def _get_inverse_name(self, name, is_company=False):
"""Try to revert the effect of :meth:`._compute_name`.
- If the partner is a company, save it in the lastname.
@ -78,15 +82,18 @@ class ResPartner(models.Model):
trimmed whitespace.
"""
# Company name goes to the lastname
if self.is_company or not self.name:
parts = [self.name or False, False]
if is_company or not name:
parts = [name or False, False]
# Guess name splitting
else:
parts = self.name.split(" ", 1)
parts = name.split(" ", 1)
while len(parts) < 2:
parts.append(False)
return parts
@api.one
def _inverse_name(self):
parts = self._get_inverse_name(self.name, self.is_company)
self.lastname, self.firstname = parts
@api.one

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