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Fix monkey patchin

pull/1379/head
hpar 7 years ago
committed by Pierrick Brun
parent
commit
bbff9dc620
  1. 120
      base_jsonify/models/models.py

120
base_jsonify/models/models.py

@ -5,74 +5,76 @@
# License AGPL-3.0 or later (http://www.gnu.org/licenses/agpl.html). # License AGPL-3.0 or later (http://www.gnu.org/licenses/agpl.html).
from odoo import api, models from odoo import api, models
from odoo.exceptions import Warning as UserError
from odoo.exceptions import UserError
from odoo.tools.translate import _ from odoo.tools.translate import _
def __parse_field(parser_field):
field_name = parser_field
subparser = None
if isinstance(parser_field, tuple):
field_name, subparser = parser_field
json_key = field_name
if ':' in field_name:
field_name, json_key = field_name.split(':')
return field_name, json_key, subparser
class Base(models.AbstractModel):
_inherit = 'base'
@api.multi
def jsonify(self, parser):
""" Convert the record according to the parser given
Example of parser:
parser = [
'name',
'number',
'create_date',
('partner_id', ['id', 'display_name', 'ref'])
('line_id', ['id', ('product_id', ['name']), 'price_unit'])
]
@api.model
def __parse_field(self, parser_field):
field_name = parser_field
subparser = None
if isinstance(parser_field, tuple):
field_name, subparser = parser_field
json_key = field_name
if ':' in field_name:
field_name, json_key = field_name.split(':')
return field_name, json_key, subparser
In order to be consitent with the odoo api the jsonify method always
return a list of object even if there is only one element in input
By default the key into the json is the name of the field extracted
from the model. If you need to specify an alternate name to use as key, you
can define your mapping as follow into the parser definition:
@api.multi
def jsonify(self, parser):
""" Convert the record according to the parser given
Example of parser:
parser = [
'name',
'number',
'create_date',
('partner_id', ['id', 'display_name', 'ref'])
('line_id', ['id', ('product_id', ['name']), 'price_unit'])
]
parser = [
'field_name:json_key'
]
In order to be consitent with the odoo api the jsonify method always
return a list of object even if there is only one element in input
"""
result = []
empty_value = {
'char': None,
'int': None,
# 'float': None, TODO: 0.0 != False
'text': None,
}
By default the key into the json is the name of the field extracted
from the model. If you need to specify an alternate name to use as key, you
can define your mapping as follow into the parser definition:
for rec in self:
res = {}
for field in parser:
field_name, json_key, subparser = __parse_field(field)
field_type = rec._fields[field_name].type
if subparser:
if field_type in ('one2many', 'many2many'):
res[json_key] = rec[field_name].jsonify(subparser)
elif field_type in ('many2one', 'reference'):
if rec[field_name]:
res[json_key] = rec[field_name].jsonify(subparser)[0]
else:
res[json_key] = None
else:
raise UserError(_('Wrong parser configuration'))
else:
res[json_key] = rec[field_name]
if not res[json_key] and field_type in empty_value:
res[json_key] = empty_value[field_type]
result.append(res)
return result
parser = [
'field_name:json_key'
]
"""
result = []
empty_value = {
'char': None,
'int': None,
# 'float': None, TODO: 0.0 != False
'text': None,
}
models.Model.jsonify = jsonify
for rec in self:
res = {}
for field in parser:
field_name, json_key, subparser = self.__parse_field(field)
field_type = rec._fields[field_name].type
if subparser:
if field_type in ('one2many', 'many2many'):
res[json_key] = rec[field_name].jsonify(subparser)
elif field_type in ('many2one', 'reference'):
if rec[field_name]:
res[json_key] = rec[field_name].jsonify(subparser)[0]
else:
res[json_key] = None
else:
raise UserError(_('Wrong parser configuration'))
else:
res[json_key] = rec[field_name]
if not res[json_key] and field_type in empty_value:
res[json_key] = empty_value[field_type]
result.append(res)
return result
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